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Feynman teaching note
Why 0.999... = 1
SubjectMath
Area tags
Math
It feels like a trick, but 0.999... (nines forever) is exactly equal to 1, not just close.
One clean argument: let x = 0.999... Then 10x = 9.999... Subtract the first from the second: 10x - x = 9.999... - 0.999..., which gives 9x = 9, so x = 1.
Another way: 1/3 = 0.333... Multiply both sides by 3: 3 x (1/3) = 0.999..., and the left side is 1. So 0.999... = 1.
The deep reason: '0.999...' is not a process that keeps crawling toward 1; it's a single number defined as the limit of the sequence 0.9, 0.99, 0.999, ... and that limit is exactly 1. There's no gap left to bridge because the gap shrinks below any size you could name.
Same topic, fresh practice—does not count as an adaptation.
Practice building on this note. If you publish, it can show “Based on” and add an adaptation.
Feedback & gaps
Clarity score: 79/100How well you know it: Can explain it simply
Explain why 'there must be a tiny gap between 0.999... and 1' is the misunderstanding to fix.
- Doesn't make the notion of a limit fully precise.
- Could address why the '10x' trick is valid for infinite decimals.
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